Solve the System of Inequalities -2m<6 and 3m>24

$- 2 m < 6$ and $3 m > 24$

Divide each term in $- 2 m < 6$ by $- 2$ and simplify.

Divide each term in $- 2 m < 6$ by $- 2$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 2 m}{- 2} > \frac{6}{- 2}$ and $3 m > 24$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 m}{- 2} > \frac{6}{- 2}$ and $3 m > 24$

Divide $m$ by $1$ .

$m > \frac{6}{- 2}$ and $3 m > 24$

Simplify the right side.

Divide $6$ by $- 2$ .

$m > - 3$ and $3 m > 24$

Divide each term in $3 m > 24$ by $3$ and simplify.

Divide each term in $3 m > 24$ by $3$ .

$m > - 3$ and $\frac{3 m}{3} > \frac{24}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$m > - 3$ and $\frac{3 m}{3} > \frac{24}{3}$

Divide $m$ by $1$ .

$m > - 3$ and $m > \frac{24}{3}$

Simplify the right side.

Divide $24$ by $3$ .

$m > - 3$ and $m > 8$

The intersection consists of the elements that are contained in both intervals.

$m > 8$

The result can be shown in multiple forms.

Inequality Form:

$m > 8$

Interval Notation:

$(8, \infty)$

Solve the System of Inequalities -2m<6 and 3m>24

Related Questions

Support LCMGCF.com by disabling your adblocker.