Solve the System of Inequalities 2y<-12x+4 y<-6x+4

$2 y < - 12 x + 4$ $y < - 6 x + 4$

Step 1

Divide each term in $2 y < - 12 x + 4$ by $2$ and simplify.

Divide each term in $2 y < - 12 x + 4$ by $2$ .

$\frac{2 y}{2} < \frac{- 12 x}{2} + \frac{4}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} < \frac{- 12 x}{2} + \frac{4}{2}$

Divide $y$ by $1$ .

$y < \frac{- 12 x}{2} + \frac{4}{2}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 12$ and $2$ .

Factor $2$ out of $- 12 x$ .

$y < \frac{2 (- 6 x)}{2} + \frac{4}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$y < \frac{2 (- 6 x)}{2 (1)} + \frac{4}{2}$

Cancel the common factor.

$y < \frac{2 (- 6 x)}{2 \cdot 1} + \frac{4}{2}$

Rewrite the expression.

$y < \frac{- 6 x}{1} + \frac{4}{2}$

Divide $- 6 x$ by $1$ .

$y < - 6 x + \frac{4}{2}$

Divide $4$ by $2$ .

$y < - 6 x + 2$

Step 2

Find the intersection of $y < - 6 x + 2$ and $y < - 6 x + 4$ .

$y < N o (Min i m u m)$

Step 3