Solve the System of Inequalities 3m>=-12 and -m-6<3

Cancel the common factor of ${\displaystyle 3}$.

${\displaystyle m\ge \frac{-12}{3}}$ and ${\displaystyle -m-6<3}$

Divide ${\displaystyle -12}$ by ${\displaystyle 3}$.

${\displaystyle m\ge -4}$ and ${\displaystyle -m-6<3}$

Add ${\displaystyle 6}$ to both sides of the inequality.

${\displaystyle m\ge -4}$ and ${\displaystyle -m<3+6}$

Add ${\displaystyle 3}$ and ${\displaystyle 6}$.

${\displaystyle m\ge -4}$ and ${\displaystyle -m<9}$

Divide each term in ${\displaystyle -m<9}$ by ${\displaystyle -1}$. When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

${\displaystyle m\ge -4}$ and ${\displaystyle \frac{-m}{-1}>\frac{9}{-1}}$

Simplify the left side.

${\displaystyle m\ge -4}$ and ${\displaystyle m>\frac{9}{-1}}$

Simplify the right side.

${\displaystyle m\ge -4}$ and ${\displaystyle m>-9}$