Solve the System of Inequalities 3m<=-21 and m+24>19

$3 m \leq - 21$ and $m + 24 > 19$

Step 1

Divide each term in $3 m \leq - 21$ by $3$ and simplify.

Divide each term in $3 m \leq - 21$ by $3$ .

$\frac{3 m}{3} \leq \frac{- 21}{3}$ and $m + 24 > 19$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 m}{3} \leq \frac{- 21}{3}$ and $m + 24 > 19$

Divide $m$ by $1$ .

$m \leq \frac{- 21}{3}$ and $m + 24 > 19$

Simplify the right side.

Divide $- 21$ by $3$ .

$m \leq - 7$ and $m + 24 > 19$

Step 2

Move all terms not containing $m$ to the right side of the inequality.

Subtract $24$ from both sides of the inequality.

$m \leq - 7$ and $m > 19 - 24$

Subtract $24$ from $19$ .

$m \leq - 7$ and $m > - 5$

Step 3

The intersection consists of the elements that are contained in both intervals.

No solution