Solve the System of Inequalities 4m+6<2 OR (m+4)/3>3

$4 m + 6 < 2$ OR $\frac{m + 4}{3} > 3$

Solve $4 m + 6 < 2$ for $m$ .

Move all terms not containing $m$ to the right side of the inequality.

Subtract $6$ from both sides of the inequality.

$4 m < 2 - 6$

Subtract $6$ from $2$ .

$4 m < - 4$

Divide each term in $4 m < - 4$ by $4$ and simplify.

Divide each term in $4 m < - 4$ by $4$ .

$\frac{4 m}{4} < \frac{- 4}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 m}{4} < \frac{- 4}{4}$

Divide $m$ by $1$ .

$m < \frac{- 4}{4}$

Simplify the right side.

Divide $- 4$ by $4$ .

$m < - 1$

Solve $\frac{m + 4}{3} > 3$ for $m$ .

Multiply both sides by $3$ .

$\frac{m + 4}{3} \cdot 3 > 3 \cdot 3$

Simplify.

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{m + 4}{3} \cdot 3 > 3 \cdot 3$

Rewrite the expression.

$m + 4 > 3 \cdot 3$

Simplify the right side.

Multiply $3$ by $3$ .

$m + 4 > 9$

Move all terms not containing $m$ to the right side of the inequality.

Subtract $4$ from both sides of the inequality.

$m > 9 - 4$

Subtract $4$ from $9$ .

$m > 5$

Find the intersection of $m < - 1$ and $m > 5$ .

No solution