Solve the System of Inequalities 6m<=-36 and m+24>20

$6 m \leq - 36$ and $m + 24 > 20$

Divide each term in $6 m \leq - 36$ by $6$ and simplify.

Divide each term in $6 m \leq - 36$ by $6$ .

$\frac{6 m}{6} \leq \frac{- 36}{6}$ and $m + 24 > 20$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 m}{6} \leq \frac{- 36}{6}$ and $m + 24 > 20$

Divide $m$ by $1$ .

$m \leq \frac{- 36}{6}$ and $m + 24 > 20$

Simplify the right side.

Divide $- 36$ by $6$ .

$m \leq - 6$ and $m + 24 > 20$

Move all terms not containing $m$ to the right side of the inequality.

Subtract $24$ from both sides of the inequality.

$m \leq - 6$ and $m > 20 - 24$

Subtract $24$ from $20$ .

$m \leq - 6$ and $m > - 4$

The intersection consists of the elements that are contained in both intervals.

No solution