Solve the System of Inequalities -6x+14<-28 OR 9x+15<=-12

$- 6 x + 14 < - 28$ OR $9 x + 15 \leq - 12$

Solve $- 6 x + 14 < - 28$ for $x$ .

Move all terms not containing $x$ to the right side of the inequality.

Subtract $14$ from both sides of the inequality.

$- 6 x < - 28 - 14$

Subtract $14$ from $- 28$ .

$- 6 x < - 42$

Divide each term in $- 6 x < - 42$ by $- 6$ and simplify.

Divide each term in $- 6 x < - 42$ by $- 6$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 6 x}{- 6} > \frac{- 42}{- 6}$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 x}{- 6} > \frac{- 42}{- 6}$

Divide $x$ by $1$ .

$x > \frac{- 42}{- 6}$

Simplify the right side.

Divide $- 42$ by $- 6$ .

$x > 7$

Solve $9 x + 15 \leq - 12$ for $x$ .

Move all terms not containing $x$ to the right side of the inequality.

Subtract $15$ from both sides of the inequality.

$9 x \leq - 12 - 15$

Subtract $15$ from $- 12$ .

$9 x \leq - 27$

Divide each term in $9 x \leq - 27$ by $9$ and simplify.

Divide each term in $9 x \leq - 27$ by $9$ .

$\frac{9 x}{9} \leq \frac{- 27}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 x}{9} \leq \frac{- 27}{9}$

Divide $x$ by $1$ .

$x \leq \frac{- 27}{9}$

Simplify the right side.

Divide $- 27$ by $9$ .

$x \leq - 3$

Find the intersection of $x > 7$ and $x \leq - 3$ .

No solution

Solve the System of Inequalities -6x+14<-28 OR 9x+15<=-12

Related Questions

Support LCMGCF.com by disabling your adblocker.