Solve the System of Inequalities 8-3x>5 and x-5>=10

$8 - 3 x > 5$ and $x - 5 \geq 10$

Simplify the first inequality.

Move all terms not containing $x$ to the right side of the inequality.

Subtract $8$ from both sides of the inequality.

$- 3 x > 5 - 8$ and $x - 5 \geq 10$

Subtract $8$ from $5$ .

$- 3 x > - 3$ and $x - 5 \geq 10$

Divide each term in $- 3 x > - 3$ by $- 3$ and simplify.

Divide each term in $- 3 x > - 3$ by $- 3$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 3 x}{- 3} < \frac{- 3}{- 3}$ and $x - 5 \geq 10$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} < \frac{- 3}{- 3}$ and $x - 5 \geq 10$

Divide $x$ by $1$ .

$x < \frac{- 3}{- 3}$ and $x - 5 \geq 10$

Simplify the right side.

Divide $- 3$ by $- 3$ .

$x < 1$ and $x - 5 \geq 10$

Move all terms not containing $x$ to the right side of the inequality.

Add $5$ to both sides of the inequality.

$x < 1$ and $x \geq 10 + 5$

Add $10$ and $5$ .

$x < 1$ and $x \geq 15$

The intersection consists of the elements that are contained in both intervals.

No solution

Solve the System of Inequalities 8-3x>5 and x-5>=10

Related Questions

Support LCMGCF.com by disabling your adblocker.