Solve the System of Inequalities k-3<-7 or k+5>=8

$k - 3 < - 7$ or $k + 5 \geq 8$

Move all terms not containing $k$ to the right side of the inequality.

Add $3$ to both sides of the inequality.

$k < - 7 + 3$ or $k + 5 \geq 8$

Add $- 7$ and $3$ .

$k < - 4$ or $k + 5 \geq 8$

Move all terms not containing $k$ to the right side of the inequality.

Subtract $5$ from both sides of the inequality.

$k < - 4$ or $k \geq 8 - 5$

Subtract $5$ from $8$ .

$k < - 4$ or $k \geq 3$

The result can be shown in multiple forms.

Inequality Form:

$k < - 4 or k \geq 3$

Interval Notation:

$(- \infty, - 4) \cup [3, \infty)$