Solve the System of Inequalities (m-2)/3<=-4 OR 3m-8>4

$\frac{m - 2}{3} \leq - 4$ OR $3 m - 8 > 4$

Solve $\frac{m - 2}{3} \leq - 4$ for $m$ .

Multiply both sides by $3$ .

$\frac{m - 2}{3} \cdot 3 \leq - 4 \cdot 3$

Simplify.

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{m - 2}{3} \cdot 3 \leq - 4 \cdot 3$

Rewrite the expression.

$m - 2 \leq - 4 \cdot 3$

Simplify the right side.

Multiply $- 4$ by $3$ .

$m - 2 \leq - 12$

Move all terms not containing $m$ to the right side of the inequality.

Add $2$ to both sides of the inequality.

$m \leq - 12 + 2$

Add $- 12$ and $2$ .

$m \leq - 10$

Solve $3 m - 8 > 4$ for $m$ .

Move all terms not containing $m$ to the right side of the inequality.

Add $8$ to both sides of the inequality.

$3 m > 4 + 8$

Add $4$ and $8$ .

$3 m > 12$

Divide each term in $3 m > 12$ by $3$ and simplify.

Divide each term in $3 m > 12$ by $3$ .

$\frac{3 m}{3} > \frac{12}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 m}{3} > \frac{12}{3}$

Divide $m$ by $1$ .

$m > \frac{12}{3}$

Simplify the right side.

Divide $12$ by $3$ .

$m > 4$

Find the intersection of $m \leq - 10$ and $m > 4$ .

No solution