Solve the System of Inequalities v+2<=6 or v-4>=12

$v + 2 \leq 6$ or $v - 4 \geq 12$

Move all terms not containing $v$ to the right side of the inequality.

Subtract $2$ from both sides of the inequality.

$v \leq 6 - 2$

Subtract $2$ from $6$ .

$v \leq 4$

Move all terms not containing $v$ to the right side of the inequality.

Add $4$ to both sides of the inequality.

$v \geq 12 + 4$

Add $12$ and $4$ .

$v \geq 16$

The union consists of all of the elements that are contained in each interval.

$v \leq 4$ or $v \geq 16$

The result can be shown in multiple forms.

Inequality Form:

$v \leq 4 or v \geq 16$

Interval Notation:

$(- \infty, 4] \cup [16, \infty)$