Solve the System of Inequalities w+3<=0 or w+7>=9

$w + 3 \leq 0$ or $w + 7 \geq 9$

Subtract $3$ from both sides of the inequality.

$w \leq - 3$

Move all terms not containing $w$ to the right side of the inequality.

Subtract $7$ from both sides of the inequality.

$w \geq 9 - 7$

Subtract $7$ from $9$ .

$w \geq 2$

The union consists of all of the elements that are contained in each interval.

$w \leq - 3$ or $w \geq 2$

The result can be shown in multiple forms.

Inequality Form:

$w \leq - 3 or w \geq 2$

Interval Notation:

$(- \infty, - 3] \cup [2, \infty)$