Solve the System of Inequalities X/4+4<3 or -x+2<2

Subtract ${\displaystyle 4}$ from both sides of the inequality.

${\displaystyle \frac{X}{4}<3-4}$ or ${\displaystyle -x+2<2}$

Subtract ${\displaystyle 4}$ from ${\displaystyle 3}$.

${\displaystyle \frac{X}{4}<-1}$ or ${\displaystyle -x+2<2}$

Simplify the left side.

${\displaystyle X<-1\cdot 4}$ or ${\displaystyle -x+2<2}$

Simplify the right side.

${\displaystyle X<-4}$ or ${\displaystyle -x+2<2}$

Subtract ${\displaystyle 2}$ from both sides of the inequality.

${\displaystyle X<-4}$ or ${\displaystyle -x<2-2}$

Subtract ${\displaystyle 2}$ from ${\displaystyle 2}$.

${\displaystyle X<-4}$ or ${\displaystyle -x<0}$

Divide each term in ${\displaystyle -x<0}$ by ${\displaystyle -1}$. When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

${\displaystyle X<-4}$ or ${\displaystyle \frac{-x}{-1}>\frac{0}{-1}}$

Simplify the left side.

${\displaystyle X<-4}$ or ${\displaystyle x>\frac{0}{-1}}$

Simplify the right side.

${\displaystyle X<-4}$ or ${\displaystyle x>0}$