Solve the System of Inequalities x-y>3 x>=6

$x - y > 3$ $x \geq 6$

Step 1

Solve $x - y > 3$ for $y$ .

Subtract $x$ from both sides of the inequality.

$- y > 3 - x$

Divide each term in $- y > 3 - x$ by $- 1$ and simplify.

Divide each term in $- y > 3 - x$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- y}{- 1} < \frac{3}{- 1} + \frac{- x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} < \frac{3}{- 1} + \frac{- x}{- 1}$

Divide $y$ by $1$ .

$y < \frac{3}{- 1} + \frac{- x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $3$ by $- 1$ .

$y < - 3 + \frac{- x}{- 1}$

Dividing two negative values results in a positive value.

$y < - 3 + \frac{x}{1}$

Divide $x$ by $1$ .

$y < - 3 + x$

Step 2

Find the intersection of $y < - 3 + x$ and $x \geq 6$ .

$6 \leq x < - 3 + x$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$6 \leq x < - 3 + x$

Interval Notation:

$[6, - 3 + x)$

Step 4

Solve the System of Inequalities x-y>3 x>=6

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