Solve the System of Inequalities y<=-2/3x-3 y>=3x+8

$y \leq - \frac{2}{3} x - 3$ $y \geq 3 x + 8$

Step 1

Simplify each term.

Combine $x$ and $\frac{2}{3}$ .

$y \leq - \frac{x \cdot 2}{3} - 3$

Move $2$ to the left of $x$ .

$y \leq - \frac{2 x}{3} - 3$

Step 2

Find the intersection of $y \leq - \frac{2 x}{3} - 3$ and $y \geq 3 x + 8$ .

$3 x + 8 \leq y \leq - \frac{2 x}{3} - 3$

Step 3