Solve the System of Inequalities y<=2x-3 y<-3/4x+8

$y \leq 2 x - 3$ $y < - \frac{3}{4} x + 8$

Simplify each term.

Combine $x$ and $\frac{3}{4}$ .

$y < - \frac{x \cdot 3}{4} + 8$

Move $3$ to the left of $x$ .

$y < - \frac{3 x}{4} + 8$

Find the intersection of $y \leq 2 x - 3$ and $y < - \frac{3 x}{4} + 8$ .

$y < N o (Min i m u m)$