Solve the System of @WORD x+2y<6 , y<3

$x + 2 y < 6$ , $y < 3$

Step 1

Solve $x + 2 y < 6$ for $y$ .

Subtract $x$ from both sides of the inequality.

$2 y < 6 - x$

Divide each term in $2 y < 6 - x$ by $2$ and simplify.

Divide each term in $2 y < 6 - x$ by $2$ .

$\frac{2 y}{2} < \frac{6}{2} + \frac{- x}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} < \frac{6}{2} + \frac{- x}{2}$

Divide $y$ by $1$ .

$y < \frac{6}{2} + \frac{- x}{2}$

Simplify the right side.

Simplify each term.

Divide $6$ by $2$ .

$y < 3 + \frac{- x}{2}$

Move the negative in front of the fraction.

$y < 3 - \frac{x}{2}$

Step 2

Find the intersection of $y < 3 - \frac{x}{2}$ and $y < 3$ .

$y < N o (Min i m u m)$

Step 3