Solve Using the Quadratic Formula 25x^2+36=0

$25 x^{2} + 36 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 25$ , $b = 0$ , and $c = 36$ into the quadratic formula and solve for $x$ .

$\frac{0 \pm \sqrt{0^{2} - 4 \cdot (25 \cdot 36)}}{2 \cdot 25}$

Step 3

Simplify.

Simplify the numerator.

Raising $0$ to any positive power yields $0$ .

$x = \frac{0 \pm \sqrt{0 - 4 \cdot 25 \cdot 36}}{2 \cdot 25}$

Multiply $- 4 \cdot 25 \cdot 36$ .

Multiply $- 4$ by $25$ .

$x = \frac{0 \pm \sqrt{0 - 100 \cdot 36}}{2 \cdot 25}$

Multiply $- 100$ by $36$ .

$x = \frac{0 \pm \sqrt{0 - 3600}}{2 \cdot 25}$

Subtract $3600$ from $0$ .

$x = \frac{0 \pm \sqrt{- 3600}}{2 \cdot 25}$

Rewrite $- 3600$ as $- 1 (3600)$ .

$x = \frac{0 \pm \sqrt{- 1 \cdot 3600}}{2 \cdot 25}$

Rewrite $\sqrt{- 1 (3600)}$ as $\sqrt{- 1} \cdot \sqrt{3600}$ .

$x = \frac{0 \pm \sqrt{- 1} \cdot \sqrt{3600}}{2 \cdot 25}$

Rewrite $\sqrt{- 1}$ as $i$ .

$x = \frac{0 \pm i \cdot \sqrt{3600}}{2 \cdot 25}$

Rewrite $3600$ as $60^{2}$ .

$x = \frac{0 \pm i \cdot \sqrt{60^{2}}}{2 \cdot 25}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{0 \pm i \cdot 60}{2 \cdot 25}$

Move $60$ to the left of $i$ .

$x = \frac{0 \pm 60 i}{2 \cdot 25}$

Multiply $2$ by $25$ .

$x = \frac{0 \pm 60 i}{50}$

Simplify $\frac{0 \pm 60 i}{50}$ .

$x = \frac{\pm 6 i}{5}$