Solve Using the Quadratic Formula 3m^2+7m=7

$3 m^{2} + 7 m = 7$

Step 1

Subtract $7$ from both sides of the equation.

$3 m^{2} + 7 m - 7 = 0$

Step 2

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 3

Substitute the values $a = 3$ , $b = 7$ , and $c = - 7$ into the quadratic formula and solve for $m$ .

$\frac{- 7 \pm \sqrt{7^{2} - 4 \cdot (3 \cdot - 7)}}{2 \cdot 3}$

Step 4

Simplify.

Simplify the numerator.

Raise $7$ to the power of $2$ .

$m = \frac{- 7 \pm \sqrt{49 - 4 \cdot 3 \cdot - 7}}{2 \cdot 3}$

Multiply $- 4 \cdot 3 \cdot - 7$ .

Multiply $- 4$ by $3$ .

$m = \frac{- 7 \pm \sqrt{49 - 12 \cdot - 7}}{2 \cdot 3}$

Multiply $- 12$ by $- 7$ .

$m = \frac{- 7 \pm \sqrt{49 + 84}}{2 \cdot 3}$

Add $49$ and $84$ .

$m = \frac{- 7 \pm \sqrt{133}}{2 \cdot 3}$

Multiply $2$ by $3$ .

$m = \frac{- 7 \pm \sqrt{133}}{6}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$m = \frac{- 7 \pm \sqrt{133}}{6}$

Decimal Form:

$m = 0.75542709 \dots, - 3.08876043 \dots$