Solve Using the Quadratic Formula 3x^2+5x-4=0

$3 x^{2} + 5 x - 4 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 3$ , $b = 5$ , and $c = - 4$ into the quadratic formula and solve for $x$ .

$\frac{- 5 \pm \sqrt{5^{2} - 4 \cdot (3 \cdot - 4)}}{2 \cdot 3}$

Step 3

Simplify.

Simplify the numerator.

Raise $5$ to the power of $2$ .

$x = \frac{- 5 \pm \sqrt{25 - 4 \cdot 3 \cdot - 4}}{2 \cdot 3}$

Multiply $- 4 \cdot 3 \cdot - 4$ .

Multiply $- 4$ by $3$ .

$x = \frac{- 5 \pm \sqrt{25 - 12 \cdot - 4}}{2 \cdot 3}$

Multiply $- 12$ by $- 4$ .

$x = \frac{- 5 \pm \sqrt{25 + 48}}{2 \cdot 3}$

Add $25$ and $48$ .

$x = \frac{- 5 \pm \sqrt{73}}{2 \cdot 3}$

Multiply $2$ by $3$ .

$x = \frac{- 5 \pm \sqrt{73}}{6}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{- 5 \pm \sqrt{73}}{6}$

Decimal Form:

$x = 0.59066729 \dots, - 2.25733395 \dots$