Solve Using the Quadratic Formula 3x^2-7x+2=0

$3 x^{2} - 7 x + 2 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 3$ , $b = - 7$ , and $c = 2$ into the quadratic formula and solve for $x$ .

$\frac{7 \pm \sqrt{{(- 7)}^{2} - 4 \cdot (3 \cdot 2)}}{2 \cdot 3}$

Step 3

Simplify.

Simplify the numerator.

Raise $- 7$ to the power of $2$ .

$x = \frac{7 \pm \sqrt{49 - 4 \cdot 3 \cdot 2}}{2 \cdot 3}$

Multiply $- 4 \cdot 3 \cdot 2$ .

Multiply $- 4$ by $3$ .

$x = \frac{7 \pm \sqrt{49 - 12 \cdot 2}}{2 \cdot 3}$

Multiply $- 12$ by $2$ .

$x = \frac{7 \pm \sqrt{49 - 24}}{2 \cdot 3}$

Subtract $24$ from $49$ .

$x = \frac{7 \pm \sqrt{25}}{2 \cdot 3}$

Rewrite $25$ as $5^{2}$ .

$x = \frac{7 \pm \sqrt{5^{2}}}{2 \cdot 3}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{7 \pm 5}{2 \cdot 3}$

Multiply $2$ by $3$ .

$x = \frac{7 \pm 5}{6}$

Step 4

The final answer is the combination of both solutions.

$x = 2, \frac{1}{3}$