Solve Using the Quadratic Formula 3x^2-8x+4=0

$3 x^{2} - 8 x + 4 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 3$ , $b = - 8$ , and $c = 4$ into the quadratic formula and solve for $x$ .

$\frac{8 \pm \sqrt{{(- 8)}^{2} - 4 \cdot (3 \cdot 4)}}{2 \cdot 3}$

Step 3

Simplify.

Simplify the numerator.

Raise $- 8$ to the power of $2$ .

$x = \frac{8 \pm \sqrt{64 - 4 \cdot 3 \cdot 4}}{2 \cdot 3}$

Multiply $- 4 \cdot 3 \cdot 4$ .

Multiply $- 4$ by $3$ .

$x = \frac{8 \pm \sqrt{64 - 12 \cdot 4}}{2 \cdot 3}$

Multiply $- 12$ by $4$ .

$x = \frac{8 \pm \sqrt{64 - 48}}{2 \cdot 3}$

Subtract $48$ from $64$ .

$x = \frac{8 \pm \sqrt{16}}{2 \cdot 3}$

Rewrite $16$ as $4^{2}$ .

$x = \frac{8 \pm \sqrt{4^{2}}}{2 \cdot 3}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{8 \pm 4}{2 \cdot 3}$

Multiply $2$ by $3$ .

$x = \frac{8 \pm 4}{6}$

Simplify $\frac{8 \pm 4}{6}$ .

$x = \frac{4 \pm 2}{3}$

Step 4

The final answer is the combination of both solutions.

$x = 2, \frac{2}{3}$