Solve Using the Quadratic Formula 3y^2-5y=1

$3 y^{2} - 5 y = 1$

Step 1

Subtract $1$ from both sides of the equation.

$3 y^{2} - 5 y - 1 = 0$

Step 2

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 3

Substitute the values $a = 3$ , $b = - 5$ , and $c = - 1$ into the quadratic formula and solve for $y$ .

$\frac{5 \pm \sqrt{{(- 5)}^{2} - 4 \cdot (3 \cdot - 1)}}{2 \cdot 3}$

Step 4

Simplify.

Simplify the numerator.

Raise $- 5$ to the power of $2$ .

$y = \frac{5 \pm \sqrt{25 - 4 \cdot 3 \cdot - 1}}{2 \cdot 3}$

Multiply $- 4 \cdot 3 \cdot - 1$ .

Multiply $- 4$ by $3$ .

$y = \frac{5 \pm \sqrt{25 - 12 \cdot - 1}}{2 \cdot 3}$

Multiply $- 12$ by $- 1$ .

$y = \frac{5 \pm \sqrt{25 + 12}}{2 \cdot 3}$

Add $25$ and $12$ .

$y = \frac{5 \pm \sqrt{37}}{2 \cdot 3}$

Multiply $2$ by $3$ .

$y = \frac{5 \pm \sqrt{37}}{6}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$y = \frac{5 \pm \sqrt{37}}{6}$

Decimal Form:

$y = 1.84712708 \dots, - 0.18046042 \dots$