Solve Using the Quadratic Formula 4t^2-7t=1

$4 t^{2} - 7 t = 1$

Step 1

Subtract $1$ from both sides of the equation.

$4 t^{2} - 7 t - 1 = 0$

Step 2

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 3

Substitute the values $a = 4$ , $b = - 7$ , and $c = - 1$ into the quadratic formula and solve for $t$ .

$\frac{7 \pm \sqrt{{(- 7)}^{2} - 4 \cdot (4 \cdot - 1)}}{2 \cdot 4}$

Step 4

Simplify.

Simplify the numerator.

Raise $- 7$ to the power of $2$ .

$t = \frac{7 \pm \sqrt{49 - 4 \cdot 4 \cdot - 1}}{2 \cdot 4}$

Multiply $- 4 \cdot 4 \cdot - 1$ .

Multiply $- 4$ by $4$ .

$t = \frac{7 \pm \sqrt{49 - 16 \cdot - 1}}{2 \cdot 4}$

Multiply $- 16$ by $- 1$ .

$t = \frac{7 \pm \sqrt{49 + 16}}{2 \cdot 4}$

Add $49$ and $16$ .

$t = \frac{7 \pm \sqrt{65}}{2 \cdot 4}$

Multiply $2$ by $4$ .

$t = \frac{7 \pm \sqrt{65}}{8}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$t = \frac{7 \pm \sqrt{65}}{8}$

Decimal Form:

$t = 1.88278221 \dots, - 0.13278221 \dots$