Solve Using the Quadratic Formula 4x^2-100=0

$4 x^{2} - 100 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 4$ , $b = 0$ , and $c = - 100$ into the quadratic formula and solve for $x$ .

$\frac{0 \pm \sqrt{0^{2} - 4 \cdot (4 \cdot - 100)}}{2 \cdot 4}$

Step 3

Simplify.

Simplify the numerator.

Raising $0$ to any positive power yields $0$ .

$x = \frac{0 \pm \sqrt{0 - 4 \cdot 4 \cdot - 100}}{2 \cdot 4}$

Multiply $- 4 \cdot 4 \cdot - 100$ .

Multiply $- 4$ by $4$ .

$x = \frac{0 \pm \sqrt{0 - 16 \cdot - 100}}{2 \cdot 4}$

Multiply $- 16$ by $- 100$ .

$x = \frac{0 \pm \sqrt{0 + 1600}}{2 \cdot 4}$

Add $0$ and $1600$ .

$x = \frac{0 \pm \sqrt{1600}}{2 \cdot 4}$

Rewrite $1600$ as $40^{2}$ .

$x = \frac{0 \pm \sqrt{40^{2}}}{2 \cdot 4}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{0 \pm 40}{2 \cdot 4}$

Multiply $2$ by $4$ .

$x = \frac{0 \pm 40}{8}$

Simplify $\frac{0 \pm 40}{8}$ .

$x = \pm 5$

Step 4

The final answer is the combination of both solutions.

$x = 5, - 5$