Solve Using the Quadratic Formula 4x^2=12

$4 x^{2} = 12$

Subtract $12$ from both sides of the equation.

$4 x^{2} - 12 = 0$

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Substitute the values $a = 4$ , $b = 0$ , and $c = - 12$ into the quadratic formula and solve for $x$ .

$\frac{0 \pm \sqrt{0^{2} - 4 \cdot (4 \cdot - 12)}}{2 \cdot 4}$

Simplify.

Simplify the numerator.

Raising $0$ to any positive power yields $0$ .

$x = \frac{0 \pm \sqrt{0 - 4 \cdot 4 \cdot - 12}}{2 \cdot 4}$

Multiply $- 4$ by $4$ .

$x = \frac{0 \pm \sqrt{0 - 16 \cdot - 12}}{2 \cdot 4}$

Multiply $- 16$ by $- 12$ .

$x = \frac{0 \pm \sqrt{0 + 192}}{2 \cdot 4}$

Add $0$ and $192$ .

$x = \frac{0 \pm \sqrt{192}}{2 \cdot 4}$

Rewrite $192$ as $8^{2} \cdot 3$ .

Factor $64$ out of $192$ .

$x = \frac{0 \pm \sqrt{64 (3)}}{2 \cdot 4}$

Rewrite $64$ as $8^{2}$ .

$x = \frac{0 \pm \sqrt{8^{2} \cdot 3}}{2 \cdot 4}$

Pull terms out from under the radical.

$x = \frac{0 \pm 8 \sqrt{3}}{2 \cdot 4}$

Multiply $2$ by $4$ .

$x = \frac{0 \pm 8 \sqrt{3}}{8}$

Simplify $\frac{0 \pm 8 \sqrt{3}}{8}$ .

$x = \pm \sqrt{3}$

The result can be shown in multiple forms.

Exact Form:

$x = \pm \sqrt{3}$

Decimal Form:

$x = 1.73205080 \dots, - 1.73205080 \dots$