Solve Using the Quadratic Formula 4x^2+25=0

$4 x^{2} + 25 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 4$ , $b = 0$ , and $c = 25$ into the quadratic formula and solve for $x$ .

$\frac{0 \pm \sqrt{0^{2} - 4 \cdot (4 \cdot 25)}}{2 \cdot 4}$

Step 3

Simplify.

Simplify the numerator.

Raising $0$ to any positive power yields $0$ .

$x = \frac{0 \pm \sqrt{0 - 4 \cdot 4 \cdot 25}}{2 \cdot 4}$

Multiply $- 4 \cdot 4 \cdot 25$ .

Multiply $- 4$ by $4$ .

$x = \frac{0 \pm \sqrt{0 - 16 \cdot 25}}{2 \cdot 4}$

Multiply $- 16$ by $25$ .

$x = \frac{0 \pm \sqrt{0 - 400}}{2 \cdot 4}$

Subtract $400$ from $0$ .

$x = \frac{0 \pm \sqrt{- 400}}{2 \cdot 4}$

Rewrite $- 400$ as $- 1 (400)$ .

$x = \frac{0 \pm \sqrt{- 1 \cdot 400}}{2 \cdot 4}$

Rewrite $\sqrt{- 1 (400)}$ as $\sqrt{- 1} \cdot \sqrt{400}$ .

$x = \frac{0 \pm \sqrt{- 1} \cdot \sqrt{400}}{2 \cdot 4}$

Rewrite $\sqrt{- 1}$ as $i$ .

$x = \frac{0 \pm i \cdot \sqrt{400}}{2 \cdot 4}$

Rewrite $400$ as $20^{2}$ .

$x = \frac{0 \pm i \cdot \sqrt{20^{2}}}{2 \cdot 4}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{0 \pm i \cdot 20}{2 \cdot 4}$

Move $20$ to the left of $i$ .

$x = \frac{0 \pm 20 i}{2 \cdot 4}$

Multiply $2$ by $4$ .

$x = \frac{0 \pm 20 i}{8}$

Simplify $\frac{0 \pm 20 i}{8}$ .

$x = \frac{\pm 5 i}{2}$