Solve Using the Quadratic Formula 4x^2+3x=10

$4 x^{2} + 3 x = 10$

Step 1

Subtract $10$ from both sides of the equation.

$4 x^{2} + 3 x - 10 = 0$

Step 2

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 3

Substitute the values $a = 4$ , $b = 3$ , and $c = - 10$ into the quadratic formula and solve for $x$ .

$\frac{- 3 \pm \sqrt{3^{2} - 4 \cdot (4 \cdot - 10)}}{2 \cdot 4}$

Step 4

Simplify.

Simplify the numerator.

Raise $3$ to the power of $2$ .

$x = \frac{- 3 \pm \sqrt{9 - 4 \cdot 4 \cdot - 10}}{2 \cdot 4}$

Multiply $- 4 \cdot 4 \cdot - 10$ .

Multiply $- 4$ by $4$ .

$x = \frac{- 3 \pm \sqrt{9 - 16 \cdot - 10}}{2 \cdot 4}$

Multiply $- 16$ by $- 10$ .

$x = \frac{- 3 \pm \sqrt{9 + 160}}{2 \cdot 4}$

Add $9$ and $160$ .

$x = \frac{- 3 \pm \sqrt{169}}{2 \cdot 4}$

Rewrite $169$ as $13^{2}$ .

$x = \frac{- 3 \pm \sqrt{13^{2}}}{2 \cdot 4}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{- 3 \pm 13}{2 \cdot 4}$

Multiply $2$ by $4$ .

$x = \frac{- 3 \pm 13}{8}$

Step 5

The final answer is the combination of both solutions.

$x = \frac{5}{4}, - 2$