Solve Using the Quadratic Formula 5t^2-7t=1

$5 t^{2} - 7 t = 1$

Step 1

Subtract $1$ from both sides of the equation.

$5 t^{2} - 7 t - 1 = 0$

Step 2

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 3

Substitute the values $a = 5$ , $b = - 7$ , and $c = - 1$ into the quadratic formula and solve for $t$ .

$\frac{7 \pm \sqrt{{(- 7)}^{2} - 4 \cdot (5 \cdot - 1)}}{2 \cdot 5}$

Step 4

Simplify.

Simplify the numerator.

Raise $- 7$ to the power of $2$ .

$t = \frac{7 \pm \sqrt{49 - 4 \cdot 5 \cdot - 1}}{2 \cdot 5}$

Multiply $- 4 \cdot 5 \cdot - 1$ .

Multiply $- 4$ by $5$ .

$t = \frac{7 \pm \sqrt{49 - 20 \cdot - 1}}{2 \cdot 5}$

Multiply $- 20$ by $- 1$ .

$t = \frac{7 \pm \sqrt{49 + 20}}{2 \cdot 5}$

Add $49$ and $20$ .

$t = \frac{7 \pm \sqrt{69}}{2 \cdot 5}$

Multiply $2$ by $5$ .

$t = \frac{7 \pm \sqrt{69}}{10}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$t = \frac{7 \pm \sqrt{69}}{10}$

Decimal Form:

$t = 1.53066238 \dots, - 0.13066238 \dots$