Solve Using the Quadratic Formula 5x^2-6x=0

$5 x^{2} - 6 x = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 5$ , $b = - 6$ , and $c = 0$ into the quadratic formula and solve for $x$ .

$\frac{6 \pm \sqrt{{(- 6)}^{2} - 4 \cdot (5 \cdot 0)}}{2 \cdot 5}$

Step 3

Simplify.

Simplify the numerator.

Raise $- 6$ to the power of $2$ .

$x = \frac{6 \pm \sqrt{36 - 4 \cdot 5 \cdot 0}}{2 \cdot 5}$

Multiply $- 4 \cdot 5 \cdot 0$ .

Multiply $- 4$ by $5$ .

$x = \frac{6 \pm \sqrt{36 - 20 \cdot 0}}{2 \cdot 5}$

Multiply $- 20$ by $0$ .

$x = \frac{6 \pm \sqrt{36 + 0}}{2 \cdot 5}$

Add $36$ and $0$ .

$x = \frac{6 \pm \sqrt{36}}{2 \cdot 5}$

Rewrite $36$ as $6^{2}$ .

$x = \frac{6 \pm \sqrt{6^{2}}}{2 \cdot 5}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{6 \pm 6}{2 \cdot 5}$

Multiply $2$ by $5$ .

$x = \frac{6 \pm 6}{10}$

Simplify $\frac{6 \pm 6}{10}$ .

$x = \frac{3 \pm 3}{5}$

Step 4

The final answer is the combination of both solutions.

$x = \frac{6}{5}, 0$