Solve Using the Quadratic Formula 5x^2-7x-2=0

$5 x^{2} - 7 x - 2 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 5$ , $b = - 7$ , and $c = - 2$ into the quadratic formula and solve for $x$ .

$\frac{7 \pm \sqrt{{(- 7)}^{2} - 4 \cdot (5 \cdot - 2)}}{2 \cdot 5}$

Step 3

Simplify.

Simplify the numerator.

Raise $- 7$ to the power of $2$ .

$x = \frac{7 \pm \sqrt{49 - 4 \cdot 5 \cdot - 2}}{2 \cdot 5}$

Multiply $- 4 \cdot 5 \cdot - 2$ .

Multiply $- 4$ by $5$ .

$x = \frac{7 \pm \sqrt{49 - 20 \cdot - 2}}{2 \cdot 5}$

Multiply $- 20$ by $- 2$ .

$x = \frac{7 \pm \sqrt{49 + 40}}{2 \cdot 5}$

Add $49$ and $40$ .

$x = \frac{7 \pm \sqrt{89}}{2 \cdot 5}$

Multiply $2$ by $5$ .

$x = \frac{7 \pm \sqrt{89}}{10}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{7 \pm \sqrt{89}}{10}$

Decimal Form:

$x = 1.64339811 \dots, - 0.24339811 \dots$