Solve Using the Quadratic Formula 5x^2+7x-6=0

$5 x^{2} + 7 x - 6 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 5$ , $b = 7$ , and $c = - 6$ into the quadratic formula and solve for $x$ .

$\frac{- 7 \pm \sqrt{7^{2} - 4 \cdot (5 \cdot - 6)}}{2 \cdot 5}$

Step 3

Simplify.

Simplify the numerator.

Raise $7$ to the power of $2$ .

$x = \frac{- 7 \pm \sqrt{49 - 4 \cdot 5 \cdot - 6}}{2 \cdot 5}$

Multiply $- 4 \cdot 5 \cdot - 6$ .

Multiply $- 4$ by $5$ .

$x = \frac{- 7 \pm \sqrt{49 - 20 \cdot - 6}}{2 \cdot 5}$

Multiply $- 20$ by $- 6$ .

$x = \frac{- 7 \pm \sqrt{49 + 120}}{2 \cdot 5}$

Add $49$ and $120$ .

$x = \frac{- 7 \pm \sqrt{169}}{2 \cdot 5}$

Rewrite $169$ as $13^{2}$ .

$x = \frac{- 7 \pm \sqrt{13^{2}}}{2 \cdot 5}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{- 7 \pm 13}{2 \cdot 5}$

Multiply $2$ by $5$ .

$x = \frac{- 7 \pm 13}{10}$

Step 4

The final answer is the combination of both solutions.

$x = \frac{3}{5}, - 2$