Solve Using the Quadratic Formula 6x^2-3x-1=0

$6 x^{2} - 3 x - 1 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 6$ , $b = - 3$ , and $c = - 1$ into the quadratic formula and solve for $x$ .

$\frac{3 \pm \sqrt{{(- 3)}^{2} - 4 \cdot (6 \cdot - 1)}}{2 \cdot 6}$

Step 3

Simplify.

Simplify the numerator.

Raise $- 3$ to the power of $2$ .

$x = \frac{3 \pm \sqrt{9 - 4 \cdot 6 \cdot - 1}}{2 \cdot 6}$

Multiply $- 4 \cdot 6 \cdot - 1$ .

Multiply $- 4$ by $6$ .

$x = \frac{3 \pm \sqrt{9 - 24 \cdot - 1}}{2 \cdot 6}$

Multiply $- 24$ by $- 1$ .

$x = \frac{3 \pm \sqrt{9 + 24}}{2 \cdot 6}$

Add $9$ and $24$ .

$x = \frac{3 \pm \sqrt{33}}{2 \cdot 6}$

Multiply $2$ by $6$ .

$x = \frac{3 \pm \sqrt{33}}{12}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{3 \pm \sqrt{33}}{12}$

Decimal Form:

$x = 0.72871355 \dots, - 0.22871355 \dots$