Solve Using the Quadratic Formula 6x^2-7=0

$6 x^{2} - 7 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 6$ , $b = 0$ , and $c = - 7$ into the quadratic formula and solve for $x$ .

$\frac{0 \pm \sqrt{0^{2} - 4 \cdot (6 \cdot - 7)}}{2 \cdot 6}$

Step 3

Simplify.

Simplify the numerator.

Raising $0$ to any positive power yields $0$ .

$x = \frac{0 \pm \sqrt{0 - 4 \cdot 6 \cdot - 7}}{2 \cdot 6}$

Multiply $- 4 \cdot 6 \cdot - 7$ .

Multiply $- 4$ by $6$ .

$x = \frac{0 \pm \sqrt{0 - 24 \cdot - 7}}{2 \cdot 6}$

Multiply $- 24$ by $- 7$ .

$x = \frac{0 \pm \sqrt{0 + 168}}{2 \cdot 6}$

Add $0$ and $168$ .

$x = \frac{0 \pm \sqrt{168}}{2 \cdot 6}$

Rewrite $168$ as $2^{2} \cdot 42$ .

Factor $4$ out of $168$ .

$x = \frac{0 \pm \sqrt{4 (42)}}{2 \cdot 6}$

Rewrite $4$ as $2^{2}$ .

$x = \frac{0 \pm \sqrt{2^{2} \cdot 42}}{2 \cdot 6}$

Pull terms out from under the radical.

$x = \frac{0 \pm 2 \sqrt{42}}{2 \cdot 6}$

Multiply $2$ by $6$ .

$x = \frac{0 \pm 2 \sqrt{42}}{12}$

Simplify $\frac{0 \pm 2 \sqrt{42}}{12}$ .

$x = \frac{\pm \sqrt{42}}{6}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{\pm \sqrt{42}}{6}$

Decimal Form:

$x = 1.08012344 \dots, - 1.08012344 \dots$