Solve Using the Quadratic Formula 6x^2-7x-4=0

$6 x^{2} - 7 x - 4 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 6$ , $b = - 7$ , and $c = - 4$ into the quadratic formula and solve for $x$ .

$\frac{7 \pm \sqrt{{(- 7)}^{2} - 4 \cdot (6 \cdot - 4)}}{2 \cdot 6}$

Step 3

Simplify.

Simplify the numerator.

Raise $- 7$ to the power of $2$ .

$x = \frac{7 \pm \sqrt{49 - 4 \cdot 6 \cdot - 4}}{2 \cdot 6}$

Multiply $- 4 \cdot 6 \cdot - 4$ .

Multiply $- 4$ by $6$ .

$x = \frac{7 \pm \sqrt{49 - 24 \cdot - 4}}{2 \cdot 6}$

Multiply $- 24$ by $- 4$ .

$x = \frac{7 \pm \sqrt{49 + 96}}{2 \cdot 6}$

Add $49$ and $96$ .

$x = \frac{7 \pm \sqrt{145}}{2 \cdot 6}$

Multiply $2$ by $6$ .

$x = \frac{7 \pm \sqrt{145}}{12}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{7 \pm \sqrt{145}}{12}$

Decimal Form:

$x = 1.58679954 \dots, - 0.42013288 \dots$