Solve Using the Quadratic Formula 6x^2-9x+2=0

$6 x^{2} - 9 x + 2 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 6$ , $b = - 9$ , and $c = 2$ into the quadratic formula and solve for $x$ .

$\frac{9 \pm \sqrt{{(- 9)}^{2} - 4 \cdot (6 \cdot 2)}}{2 \cdot 6}$

Step 3

Simplify.

Simplify the numerator.

Raise $- 9$ to the power of $2$ .

$x = \frac{9 \pm \sqrt{81 - 4 \cdot 6 \cdot 2}}{2 \cdot 6}$

Multiply $- 4 \cdot 6 \cdot 2$ .

Multiply $- 4$ by $6$ .

$x = \frac{9 \pm \sqrt{81 - 24 \cdot 2}}{2 \cdot 6}$

Multiply $- 24$ by $2$ .

$x = \frac{9 \pm \sqrt{81 - 48}}{2 \cdot 6}$

Subtract $48$ from $81$ .

$x = \frac{9 \pm \sqrt{33}}{2 \cdot 6}$

Multiply $2$ by $6$ .

$x = \frac{9 \pm \sqrt{33}}{12}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{9 \pm \sqrt{33}}{12}$

Decimal Form:

$x = 1.22871355 \dots, 0.27128644 \dots$