Solve Using the Quadratic Formula 7x^2-9x+2=0

$7 x^{2} - 9 x + 2 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 7$ , $b = - 9$ , and $c = 2$ into the quadratic formula and solve for $x$ .

$\frac{9 \pm \sqrt{{(- 9)}^{2} - 4 \cdot (7 \cdot 2)}}{2 \cdot 7}$

Step 3

Simplify.

Simplify the numerator.

Raise $- 9$ to the power of $2$ .

$x = \frac{9 \pm \sqrt{81 - 4 \cdot 7 \cdot 2}}{2 \cdot 7}$

Multiply $- 4 \cdot 7 \cdot 2$ .

Multiply $- 4$ by $7$ .

$x = \frac{9 \pm \sqrt{81 - 28 \cdot 2}}{2 \cdot 7}$

Multiply $- 28$ by $2$ .

$x = \frac{9 \pm \sqrt{81 - 56}}{2 \cdot 7}$

Subtract $56$ from $81$ .

$x = \frac{9 \pm \sqrt{25}}{2 \cdot 7}$

Rewrite $25$ as $5^{2}$ .

$x = \frac{9 \pm \sqrt{5^{2}}}{2 \cdot 7}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{9 \pm 5}{2 \cdot 7}$

Multiply $2$ by $7$ .

$x = \frac{9 \pm 5}{14}$

Step 4

The final answer is the combination of both solutions.

$x = 1, \frac{2}{7}$