Solve Using the Quadratic Formula x^2+11x-6=0

$x^{2} + 11 x - 6 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 1$ , $b = 11$ , and $c = - 6$ into the quadratic formula and solve for $x$ .

$\frac{- 11 \pm \sqrt{11^{2} - 4 \cdot (1 \cdot - 6)}}{2 \cdot 1}$

Step 3

Simplify.

Simplify the numerator.

Raise $11$ to the power of $2$ .

$x = \frac{- 11 \pm \sqrt{121 - 4 \cdot 1 \cdot - 6}}{2 \cdot 1}$

Multiply $- 4 \cdot 1 \cdot - 6$ .

Multiply $- 4$ by $1$ .

$x = \frac{- 11 \pm \sqrt{121 - 4 \cdot - 6}}{2 \cdot 1}$

Multiply $- 4$ by $- 6$ .

$x = \frac{- 11 \pm \sqrt{121 + 24}}{2 \cdot 1}$

Add $121$ and $24$ .

$x = \frac{- 11 \pm \sqrt{145}}{2 \cdot 1}$

Multiply $2$ by $1$ .

$x = \frac{- 11 \pm \sqrt{145}}{2}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{- 11 \pm \sqrt{145}}{2}$

Decimal Form:

$x = 0.52079728 \dots, - 11.52079728 \dots$