Solve Using the Quadratic Formula x^2+2x-33=0

$x^{2} + 2 x - 33 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 1$ , $b = 2$ , and $c = - 33$ into the quadratic formula and solve for $x$ .

$\frac{- 2 \pm \sqrt{2^{2} - 4 \cdot (1 \cdot - 33)}}{2 \cdot 1}$

Step 3

Simplify.

Simplify the numerator.

Raise $2$ to the power of $2$ .

$x = \frac{- 2 \pm \sqrt{4 - 4 \cdot 1 \cdot - 33}}{2 \cdot 1}$

Multiply $- 4 \cdot 1 \cdot - 33$ .

Multiply $- 4$ by $1$ .

$x = \frac{- 2 \pm \sqrt{4 - 4 \cdot - 33}}{2 \cdot 1}$

Multiply $- 4$ by $- 33$ .

$x = \frac{- 2 \pm \sqrt{4 + 132}}{2 \cdot 1}$

Add $4$ and $132$ .

$x = \frac{- 2 \pm \sqrt{136}}{2 \cdot 1}$

Rewrite $136$ as $2^{2} \cdot 34$ .

Factor $4$ out of $136$ .

$x = \frac{- 2 \pm \sqrt{4 (34)}}{2 \cdot 1}$

Rewrite $4$ as $2^{2}$ .

$x = \frac{- 2 \pm \sqrt{2^{2} \cdot 34}}{2 \cdot 1}$

Pull terms out from under the radical.

$x = \frac{- 2 \pm 2 \sqrt{34}}{2 \cdot 1}$

Multiply $2$ by $1$ .

$x = \frac{- 2 \pm 2 \sqrt{34}}{2}$

Simplify $\frac{- 2 \pm 2 \sqrt{34}}{2}$ .

$x = - 1 \pm \sqrt{34}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = - 1 \pm \sqrt{34}$

Decimal Form:

$x = 4.83095189 \dots, - 6.83095189 \dots$