Solve Using the Quadratic Formula x^2+6x=-x+30

$x^{2} + 6 x = - x + 30$

Move all terms to the left side of the equation and simplify.

Move all the expressions to the left side of the equation.

Add $x$ to both sides of the equation.

$x^{2} + 6 x + x = 30$

Subtract $30$ from both sides of the equation.

$x^{2} + 6 x + x - 30 = 0$

Add $6 x$ and $x$ .

$x^{2} + 7 x - 30 = 0$

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Substitute the values $a = 1$ , $b = 7$ , and $c = - 30$ into the quadratic formula and solve for $x$ .

$\frac{- 7 \pm \sqrt{7^{2} - 4 \cdot (1 \cdot - 30)}}{2 \cdot 1}$

Simplify.

Simplify the numerator.

Raise $7$ to the power of $2$ .

$x = \frac{- 7 \pm \sqrt{49 - 4 \cdot 1 \cdot - 30}}{2 \cdot 1}$

Multiply $- 4$ by $1$ .

$x = \frac{- 7 \pm \sqrt{49 - 4 \cdot - 30}}{2 \cdot 1}$

Multiply $- 4$ by $- 30$ .

$x = \frac{- 7 \pm \sqrt{49 + 120}}{2 \cdot 1}$

Add $49$ and $120$ .

$x = \frac{- 7 \pm \sqrt{169}}{2 \cdot 1}$

Rewrite $169$ as $13^{2}$ .

$x = \frac{- 7 \pm \sqrt{13^{2}}}{2 \cdot 1}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{- 7 \pm 13}{2 \cdot 1}$

Multiply $2$ by $1$ .

$x = \frac{- 7 \pm 13}{2}$

The final answer is the combination of both solutions.

$x = 3, - 10$