Solve Using the Quadratic Formula x^2+7x-60=0

$x^{2} + 7 x - 60 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 1$ , $b = 7$ , and $c = - 60$ into the quadratic formula and solve for $x$ .

$\frac{- 7 \pm \sqrt{7^{2} - 4 \cdot (1 \cdot - 60)}}{2 \cdot 1}$

Step 3

Simplify.

Simplify the numerator.

Raise $7$ to the power of $2$ .

$x = \frac{- 7 \pm \sqrt{49 - 4 \cdot 1 \cdot - 60}}{2 \cdot 1}$

Multiply $- 4 \cdot 1 \cdot - 60$ .

Multiply $- 4$ by $1$ .

$x = \frac{- 7 \pm \sqrt{49 - 4 \cdot - 60}}{2 \cdot 1}$

Multiply $- 4$ by $- 60$ .

$x = \frac{- 7 \pm \sqrt{49 + 240}}{2 \cdot 1}$

Add $49$ and $240$ .

$x = \frac{- 7 \pm \sqrt{289}}{2 \cdot 1}$

Rewrite $289$ as $17^{2}$ .

$x = \frac{- 7 \pm \sqrt{17^{2}}}{2 \cdot 1}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{- 7 \pm 17}{2 \cdot 1}$

Multiply $2$ by $1$ .

$x = \frac{- 7 \pm 17}{2}$

Step 4

The final answer is the combination of both solutions.

$x = 5, - 12$