Solve Using the Quadratic Formula x^2+8x=-6

$x^{2} + 8 x = - 6$

Step 1

Add $6$ to both sides of the equation.

$x^{2} + 8 x + 6 = 0$

Step 2

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 3

Substitute the values $a = 1$ , $b = 8$ , and $c = 6$ into the quadratic formula and solve for $x$ .

$\frac{- 8 \pm \sqrt{8^{2} - 4 \cdot (1 \cdot 6)}}{2 \cdot 1}$

Step 4

Simplify.

Simplify the numerator.

Raise $8$ to the power of $2$ .

$x = \frac{- 8 \pm \sqrt{64 - 4 \cdot 1 \cdot 6}}{2 \cdot 1}$

Multiply $- 4 \cdot 1 \cdot 6$ .

Multiply $- 4$ by $1$ .

$x = \frac{- 8 \pm \sqrt{64 - 4 \cdot 6}}{2 \cdot 1}$

Multiply $- 4$ by $6$ .

$x = \frac{- 8 \pm \sqrt{64 - 24}}{2 \cdot 1}$

Subtract $24$ from $64$ .

$x = \frac{- 8 \pm \sqrt{40}}{2 \cdot 1}$

Rewrite $40$ as $2^{2} \cdot 10$ .

Factor $4$ out of $40$ .

$x = \frac{- 8 \pm \sqrt{4 (10)}}{2 \cdot 1}$

Rewrite $4$ as $2^{2}$ .

$x = \frac{- 8 \pm \sqrt{2^{2} \cdot 10}}{2 \cdot 1}$

Pull terms out from under the radical.

$x = \frac{- 8 \pm 2 \sqrt{10}}{2 \cdot 1}$

Multiply $2$ by $1$ .

$x = \frac{- 8 \pm 2 \sqrt{10}}{2}$

Simplify $\frac{- 8 \pm 2 \sqrt{10}}{2}$ .

$x = - 4 \pm \sqrt{10}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$x = - 4 \pm \sqrt{10}$

Decimal Form:

$x = - 0.83772233 \dots, - 7.16227766 \dots$