Solve Using the Quadratic Formula x^2-9x-5=0

$x^{2} - 9 x - 5 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 1$ , $b = - 9$ , and $c = - 5$ into the quadratic formula and solve for $x$ .

$\frac{9 \pm \sqrt{{(- 9)}^{2} - 4 \cdot (1 \cdot - 5)}}{2 \cdot 1}$

Step 3

Simplify.

Simplify the numerator.

Raise $- 9$ to the power of $2$ .

$x = \frac{9 \pm \sqrt{81 - 4 \cdot 1 \cdot - 5}}{2 \cdot 1}$

Multiply $- 4 \cdot 1 \cdot - 5$ .

Multiply $- 4$ by $1$ .

$x = \frac{9 \pm \sqrt{81 - 4 \cdot - 5}}{2 \cdot 1}$

Multiply $- 4$ by $- 5$ .

$x = \frac{9 \pm \sqrt{81 + 20}}{2 \cdot 1}$

Add $81$ and $20$ .

$x = \frac{9 \pm \sqrt{101}}{2 \cdot 1}$

Multiply $2$ by $1$ .

$x = \frac{9 \pm \sqrt{101}}{2}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{9 \pm \sqrt{101}}{2}$

Decimal Form:

$x = 9.52493781 \dots, - 0.52493781 \dots$