Solve Using the Quadratic Formula x=(3+- square root of (-3)^2-42-5)/(2(2))

$x = \frac{3 + - \sqrt{{(- 3)}^{2} - 4 \cdot 2 \cdot - 5}}{2 (2)}$

Replace all occurrences of $+$ $-$ with a single $-$ . A plus sign followed by a minus sign has the same mathematical meaning as a single minus sign because $1 \cdot - 1 = - 1$

$x = \frac{3 - \sqrt{{(- 3)}^{2} - 4 \cdot 2 \cdot - 5}}{2 (2)}$

Move all terms to the left side of the equation and simplify.

Simplify the right side.

Simplify $\frac{3 - \sqrt{{(- 3)}^{2} - 4 \cdot 2 \cdot - 5}}{2 (2)}$ .

Simplify the numerator.

Raise $- 3$ to the power of $2$ .

$x = \frac{3 - \sqrt{9 - 4 \cdot 2 \cdot - 5}}{2 (2)}$

Multiply $- 4$ by $2$ .

$x = \frac{3 - \sqrt{9 - 8 \cdot - 5}}{2 (2)}$

Multiply $- 8$ by $- 5$ .

$x = \frac{3 - \sqrt{9 + 40}}{2 (2)}$

Add $9$ and $40$ .

$x = \frac{3 - \sqrt{49}}{2 (2)}$

Rewrite $49$ as $7^{2}$ .

$x = \frac{3 - \sqrt{7^{2}}}{2 (2)}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{3 - 1 \cdot 7}{2 (2)}$

Multiply $- 1$ by $7$ .

$x = \frac{3 - 7}{2 (2)}$

Subtract $7$ from $3$ .

$x = \frac{- 4}{2 (2)}$

Simplify the expression.

Multiply $2$ by $2$ .

$x = \frac{- 4}{4}$

Divide $- 4$ by $4$ .

$x = - 1$

Add $1$ to both sides of the equation.

$x + 1 = 0$

Subtract $1$ from both sides of the equation.

$x = - 1$

Solve Using the Quadratic Formula x=(3+- square root of (-3)^2-4*2*-5)/(2(2))

Related Questions

Support LCMGCF.com by disabling your adblocker.

Solve Using the Quadratic Formula x=(3+- square root of (-3)^2-42-5)/(2(2))