Solve Using the Quadratic Formula x^4-36

$x^{4} - 36$

Set $x^{4} - 36$ equal to $0$ .

$x^{4} - 36 = 0$

Add $36$ to both sides of the equation.

$x^{4} = 36$

Take the 4th root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt[4]{36}$

Simplify $\pm \sqrt[4]{36}$ .

Rewrite $36$ as $6^{2}$ .

$x = \pm \sqrt[4]{6^{2}}$

Rewrite $\sqrt[4]{6^{2}}$ as $\sqrt{\sqrt{6^{2}}}$ .

$x = \pm \sqrt{\sqrt{6^{2}}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm \sqrt{6}$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = \sqrt{6}$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - \sqrt{6}$

The complete solution is the result of both the positive and negative portions of the solution.

$x = \sqrt{6}, - \sqrt{6}$

The result can be shown in multiple forms.

Exact Form:

$x = \sqrt{6}, - \sqrt{6}$

Decimal Form:

$x = 2.44948974 \dots, - 2.44948974 \dots$