Solve Using the Quadratic Formula y^2+11=8y

$y^{2} + 11 = 8 y$

Step 1

Subtract $8 y$ from both sides of the equation.

$y^{2} + 11 - 8 y = 0$

Step 2

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 3

Substitute the values $a = 1$ , $b = - 8$ , and $c = 11$ into the quadratic formula and solve for $y$ .

$\frac{8 \pm \sqrt{{(- 8)}^{2} - 4 \cdot (1 \cdot 11)}}{2 \cdot 1}$

Step 4

Simplify.

Simplify the numerator.

Raise $- 8$ to the power of $2$ .

$y = \frac{8 \pm \sqrt{64 - 4 \cdot 1 \cdot 11}}{2 \cdot 1}$

Multiply $- 4 \cdot 1 \cdot 11$ .

Multiply $- 4$ by $1$ .

$y = \frac{8 \pm \sqrt{64 - 4 \cdot 11}}{2 \cdot 1}$

Multiply $- 4$ by $11$ .

$y = \frac{8 \pm \sqrt{64 - 44}}{2 \cdot 1}$

Subtract $44$ from $64$ .

$y = \frac{8 \pm \sqrt{20}}{2 \cdot 1}$

Rewrite $20$ as $2^{2} \cdot 5$ .

Factor $4$ out of $20$ .

$y = \frac{8 \pm \sqrt{4 (5)}}{2 \cdot 1}$

Rewrite $4$ as $2^{2}$ .

$y = \frac{8 \pm \sqrt{2^{2} \cdot 5}}{2 \cdot 1}$

Pull terms out from under the radical.

$y = \frac{8 \pm 2 \sqrt{5}}{2 \cdot 1}$

Multiply $2$ by $1$ .

$y = \frac{8 \pm 2 \sqrt{5}}{2}$

Simplify $\frac{8 \pm 2 \sqrt{5}}{2}$ .

$y = 4 \pm \sqrt{5}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$y = 4 \pm \sqrt{5}$

Decimal Form:

$y = 6.23606797 \dots, 1.76393202 \dots$