Solve Using the Quadratic Formula y=-3x^2+x+12

$y = - 3 x^{2} + x + 12$

Move all the expressions to the left side of the equation.

Add $3 x^{2}$ to both sides of the equation.

$y + 3 x^{2} = x + 12$

Subtract $x$ from both sides of the equation.

$y + 3 x^{2} - x = 12$

Subtract $12$ from both sides of the equation.

$y + 3 x^{2} - x - 12 = 0$

Move all terms not containing $y$ to the right side of the equation.

Subtract $3 x^{2}$ from both sides of the equation.

$y - x - 12 = - 3 x^{2}$

Add $x$ to both sides of the equation.

$y - 12 = - 3 x^{2} + x$

Add $12$ to both sides of the equation.

$y = - 3 x^{2} + x + 12$