Solve Using the Square Root Property (2x+4)^2=64

${(2 x + 4)}^{2} = 64$

Step 1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$2 x + 4 = \pm \sqrt{64}$

Step 2

Simplify $\pm \sqrt{64}$ .

Rewrite $64$ as $8^{2}$ .

$2 x + 4 = \pm \sqrt{8^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$2 x + 4 = \pm 8$

Step 3

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$2 x + 4 = 8$

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$2 x = 8 - 4$

Subtract $4$ from $8$ .

$2 x = 4$

Divide each term in $2 x = 4$ by $2$ and simplify.

Divide each term in $2 x = 4$ by $2$ .

$\frac{2 x}{2} = \frac{4}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{4}{2}$

Divide $x$ by $1$ .

$x = \frac{4}{2}$

Simplify the right side.

Divide $4$ by $2$ .

$x = 2$

Next, use the negative value of the $\pm$ to find the second solution.

$2 x + 4 = - 8$

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$2 x = - 8 - 4$

Subtract $4$ from $- 8$ .

$2 x = - 12$

Divide each term in $2 x = - 12$ by $2$ and simplify.

Divide each term in $2 x = - 12$ by $2$ .

$\frac{2 x}{2} = \frac{- 12}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 12}{2}$

Divide $x$ by $1$ .

$x = \frac{- 12}{2}$

Simplify the right side.

Divide $- 12$ by $2$ .

$x = - 6$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 2, - 6$

Solve Using the Square Root Property (2x+4)^2=64

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