Solve Using the Square Root Property (2x-5)^2=49

${(2 x - 5)}^{2} = 49$

Step 1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$2 x - 5 = \pm \sqrt{49}$

Step 2

Simplify $\pm \sqrt{49}$ .

Rewrite $49$ as $7^{2}$ .

$2 x - 5 = \pm \sqrt{7^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$2 x - 5 = \pm 7$

Step 3

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$2 x - 5 = 7$

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$2 x = 7 + 5$

Add $7$ and $5$ .

$2 x = 12$

Divide each term in $2 x = 12$ by $2$ and simplify.

Divide each term in $2 x = 12$ by $2$ .

$\frac{2 x}{2} = \frac{12}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{12}{2}$

Divide $x$ by $1$ .

$x = \frac{12}{2}$

Simplify the right side.

Divide $12$ by $2$ .

$x = 6$

Next, use the negative value of the $\pm$ to find the second solution.

$2 x - 5 = - 7$

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$2 x = - 7 + 5$

Add $- 7$ and $5$ .

$2 x = - 2$

Divide each term in $2 x = - 2$ by $2$ and simplify.

Divide each term in $2 x = - 2$ by $2$ .

$\frac{2 x}{2} = \frac{- 2}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 2}{2}$

Divide $x$ by $1$ .

$x = \frac{- 2}{2}$

Simplify the right side.

Divide $- 2$ by $2$ .

$x = - 1$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 6, - 1$

Solve Using the Square Root Property (2x-5)^2=49

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