Solve Using the Square Root Property (2y+7)^2=49

${(2 y + 7)}^{2} = 49$

Step 1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$2 y + 7 = \pm \sqrt{49}$

Step 2

Simplify $\pm \sqrt{49}$ .

Rewrite $49$ as $7^{2}$ .

$2 y + 7 = \pm \sqrt{7^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$2 y + 7 = \pm 7$

Step 3

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$2 y + 7 = 7$

Move all terms not containing $y$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$2 y = 7 - 7$

Subtract $7$ from $7$ .

$2 y = 0$

Divide each term in $2 y = 0$ by $2$ and simplify.

Divide each term in $2 y = 0$ by $2$ .

$\frac{2 y}{2} = \frac{0}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{0}{2}$

Divide $y$ by $1$ .

$y = \frac{0}{2}$

Simplify the right side.

Divide $0$ by $2$ .

$y = 0$

Next, use the negative value of the $\pm$ to find the second solution.

$2 y + 7 = - 7$

Move all terms not containing $y$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$2 y = - 7 - 7$

Subtract $7$ from $- 7$ .

$2 y = - 14$

Divide each term in $2 y = - 14$ by $2$ and simplify.

Divide each term in $2 y = - 14$ by $2$ .

$\frac{2 y}{2} = \frac{- 14}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{- 14}{2}$

Divide $y$ by $1$ .

$y = \frac{- 14}{2}$

Simplify the right side.

Divide $- 14$ by $2$ .

$y = - 7$

The complete solution is the result of both the positive and negative portions of the solution.

$y = 0, - 7$

Solve Using the Square Root Property (2y+7)^2=49

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